What are the solutions to the equation solvefor X,X^2+4XY+4Y^2=0 ?

The solutions to the equation solvefor X,X^2+4XY+4Y^2=0 are X=-2Y

Find the zeros of solvefor X,X^2+4XY+4Y^2=0

The zeros of solvefor X,X^2+4XY+4Y^2=0 are X=-2Y

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solve for

X, X^{2} + 4 X Y + 4 Y^{2} = 0

X = - 2 Y

Solution steps

X^{2} + 4 X Y + 4 Y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

X^{2} + 4 Y X + 4 Y^{2} = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 4 Y \pm ( 4 Y ) ^{2} - 4 \cdot 1 \cdot 4 Y ^{2}}{2 \cdot 1}

(4 Y)^{2} - 4 \cdot 1 \cdot 4 Y^{2} = 0

X_{1, 2} = \frac{- 4 Y \pm 0}{2 \cdot 1}

X = \frac{- 4 Y}{2 \cdot 1}

Simplify

\frac{- 4 Y}{2 \cdot 1} : - 2 Y

X = - 2 Y

The solution to the quadratic equation is:

X = - 2 Y

ln ∣ 0 + 2 ∣ + C = 2

96 = - 24 a

x, 5 x - 10 y = 30

5 x = 2 x + 15

6 = 4 - 5 x

What are the solutions to the equation solvefor X,X^2+4XY+4Y^2=0 ?
The solutions to the equation solvefor X,X^2+4XY+4Y^2=0 are X=-2Y
Find the zeros of solvefor X,X^2+4XY+4Y^2=0
The zeros of solvefor X,X^2+4XY+4Y^2=0 are X=-2Y