What is the answer to (r+5)/4+(r-2)/3 =7 ?

The answer to (r+5)/4+(r-2)/3 =7 is r=11

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(r+5)/4+(r-2)/3 =7

\frac{r + 5}{4} + \frac{r - 2}{3} = 7

r = 11

Solution steps

\frac{r + 5}{4} + \frac{r - 2}{3} = 7

Multiply by LCM

3 (r + 5) + 4 (r - 2) = 84

Expand

3 (r + 5) + 4 (r - 2) : 7 r + 7

7 r + 7 = 84

Move

7

to the right side

7 r = 77

Divide both sides by

7

r = 11

5 (4 w - 2) = 8 + 2 (w - 6) + 12

\frac{1}{3} (12 y - 3) - 2 (y - \frac{7}{2}) = \frac{3}{2} (6 y - 8)

28 = - 6 w - 12 + 2 w

\frac{x + 1}{40} = \frac{2}{16}

x, 8 x - 2 y = 2

What is the answer to (r+5)/4+(r-2)/3 =7 ?
The answer to (r+5)/4+(r-2)/3 =7 is r=11
Solve for r: (r+5)/4+(r-2)/3 =7
The solution is r=11