What are the solutions to the equation 10m^2+52m=-10 ?

The solutions to the equation 10m^2+52m=-10 are m=-1/5 ,m=-5

Find the zeros of 10m^2+52m=-10

The zeros of 10m^2+52m=-10 are m=-1/5 ,m=-5

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10 m^{2} + 52 m = - 10

m = - \frac{1}{5}, m = - 5

Decimal Notation

m = - 0.2, m = - 5

Solution steps

10 m^{2} + 52 m = - 10

Move

10

to the left side

10 m^{2} + 52 m + 10 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 52 \pm 5 2 ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

5 2^{2} - 4 \cdot 10 \cdot 10 = 48

m_{1, 2} = \frac{- 52 \pm 48}{2 \cdot 10}

Separate the solutions

m_{1} = \frac{- 52 + 48}{2 \cdot 10}, m_{2} = \frac{- 52 - 48}{2 \cdot 10}

m = \frac{- 52 + 48}{2 \cdot 10} : - \frac{1}{5}

m = \frac{- 52 - 48}{2 \cdot 10} : - 5

The solutions to the quadratic equation are:

m = - \frac{1}{5}, m = - 5

\frac{2 x + 2}{3} + \frac{5 x + x}{6} = \frac{15 + 2 x}{12}

\frac{11}{15} + (- \frac{3}{4})

\frac{5 ^{4}}{5} + 4

(3^{3})^{3}

2 x + 7 x - 490

What are the solutions to the equation 10m^2+52m=-10 ?
The solutions to the equation 10m^2+52m=-10 are m=-1/5 ,m=-5
Find the zeros of 10m^2+52m=-10
The zeros of 10m^2+52m=-10 are m=-1/5 ,m=-5