What is the answer to (4x)/(2a+b)-3=-3/2 ?

The answer to (4x)/(2a+b)-3=-3/2 is x=(3(2a+b))/8 ;\quad 2a+b\ne 0

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(4x)/(2a+b)-3=-3/2

\frac{4 x}{2 a + b} - 3 = - \frac{3}{2}

x = \frac{3 ( 2 a + b )}{8}; 2 a + b \neq = 0

Solution steps

\frac{4 x}{2 a + b} - 3 = - \frac{3}{2}

Move

3

to the right side

\frac{4 x}{2 a + b} = \frac{3}{2}

Multiply both sides by

2 a + b

4 x = \frac{3 ( 2 a + b )}{2}; 2 a + b \neq = 0

Divide both sides by

4; 2 a + b \neq = 0

x = \frac{3 ( 2 a + b )}{8}; 2 a + b \neq = 0

7 y - 8 = 6 y + 1

a, a + 2 b = 4

\frac{a}{- 2} = - 3

2 h - 18 = - 10

8 x - 7 = x - 7 + 4 x - 10

What is the answer to (4x)/(2a+b)-3=-3/2 ?
The answer to (4x)/(2a+b)-3=-3/2 is x=(3(2a+b))/8 ;\quad 2a+b\ne 0