What is the answer to x^2-8x+10=(x-2)^2 ?

The answer to x^2-8x+10=(x-2)^2 is x= 3/2

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x^2-8x+10=(x-2)^2

x^{2} - 8 x + 10 = (x - 2)^{2}

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

x^{2} - 8 x + 10 = (x - 2)^{2}

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

x^{2} - 8 x + 10 = x^{2} - 4 x + 4

Move

10

to the right side

x^{2} - 8 x = x^{2} - 4 x - 6

Subtract

x^{2} - 4 x

from both sides

x^{2} - 8 x - (x^{2} - 4 x) = x^{2} - 4 x - 6 - (x^{2} - 4 x)

Simplify

- 4 x = - 6

Divide both sides by

- 4

x = \frac{3}{2}

y, 3 x - 4 y = 6

\frac{1}{3} x + 2 = x - 4

u, - 2 u + 6 v = 9

5 x - 4 = 4 x - 2

f = \frac{1}{1}

What is the answer to x^2-8x+10=(x-2)^2 ?
The answer to x^2-8x+10=(x-2)^2 is x= 3/2
Solve for x: x^2-8x+10=(x-2)^2
The solution is x= 3/2