What is the answer to solvefor a,T^3=D(2+a) ?

The answer to solvefor a,T^3=D(2+a) is a=(T^3)/D-2;\quad D\ne 0

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solvefor a,T^3=D(2+a)

solve for

a, T^{3} = D (2 + a)

a = \frac{T ^{3}}{D} - 2; D \neq = 0

Solution steps

T^{3} = D (2 + a)

Switch sides

D (2 + a) = T^{3}

Divide both sides by

D; D \neq = 0

2 + a = \frac{T ^{3}}{D}; D \neq = 0

Move

2

to the right side

a = \frac{T ^{3}}{D} - 2; D \neq = 0

x, 5 x - 2 = 8 + 5 y

\frac{2}{3} + \frac{3 x}{4} = \frac{71}{12}

3 + 5 q = 9 + 4 q

\frac{x}{6153.12} \cdot 100 = 0.6

x, x - 8 y = 16

What is the answer to solvefor a,T^3=D(2+a) ?
The answer to solvefor a,T^3=D(2+a) is a=(T^3)/D-2;\quad D\ne 0