What are the solutions to the equation x^2-4x-117=0 ?

The solutions to the equation x^2-4x-117=0 are x=13,x=-9

Find the zeros of x^2-4x-117=0

The zeros of x^2-4x-117=0 are x=13,x=-9

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x^{2} - 4 x - 117 = 0

x = 13, x = - 9

Solution steps

x^{2} - 4 x - 117 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 117 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 117) = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 22}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 22}{2 \cdot 1}

x = \frac{- ( - 4 ) + 22}{2 \cdot 1} : 13

x = \frac{- ( - 4 ) - 22}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 13, x = - 9

- 2 x^{2} + 5 x - 2 = 0

\frac{- 3 g ^{- 2} h k ^{- 2}}{- 6 h ^{0}}

3^{n + 2} + 3^{n}

(2 x + 1) (x + 1) = 5 (x + 1)

x^{3} + x^{2} - 2

What are the solutions to the equation x^2-4x-117=0 ?
The solutions to the equation x^2-4x-117=0 are x=13,x=-9
Find the zeros of x^2-4x-117=0
The zeros of x^2-4x-117=0 are x=13,x=-9