What are the solutions to the equation 4x^2+49=0 ?

The solutions to the equation 4x^2+49=0 are x= 7/2 i,x=-7/2 i

Find the zeros of 4x^2+49=0

The zeros of 4x^2+49=0 are x= 7/2 i,x=-7/2 i

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4 x^{2} + 49 = 0

x = \frac{7}{2} i, x = - \frac{7}{2} i

Solution steps

4 x^{2} + 49 = 0

Move

49

to the right side

4 x^{2} = - 49

Divide both sides by

4

x^{2} = - \frac{49}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{49}{4}, x = - - \frac{49}{4}

- \frac{49}{4} = \frac{7}{2} i

- - \frac{49}{4} = - \frac{7}{2} i

x = \frac{7}{2} i, x = - \frac{7}{2} i

121 r^{3} s^{4} + 77 r^{2} s^{4} - 55 r^{4} s^{3}

x^{2} - 2 x + 1 = 16 (x - 4)

x y^{3} - 9 x y z^{2}

3 (x - 3) = 6

What are the solutions to the equation 4x^2+49=0 ?
The solutions to the equation 4x^2+49=0 are x= 7/2 i,x=-7/2 i
Find the zeros of 4x^2+49=0
The zeros of 4x^2+49=0 are x= 7/2 i,x=-7/2 i