What is the answer to solvefor A,z= A/(y^{10)}+Be^y ?

The answer to solvefor A,z= A/(y^{10)}+Be^y is A=zy^{10}-Be^yy^{10};\quad y\ne 0

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solvefor A,z= A/(y^{10)}+Be^y

solve for

A, z = \frac{A}{y ^{10}} + B e^{y}

A = z y^{10} - B e^{y} y^{10}; y \neq = 0

Solution steps

z = \frac{A}{y ^{10}} + B e^{y}

Switch sides

\frac{A}{y ^{10}} + B e^{y} = z

Move

B e^{y}

to the right side

\frac{A}{y ^{10}} = z - B e^{y}

Multiply both sides by

y^{10}

A = z y^{10} - B e^{y} y^{10}; y \neq = 0

x + x = x

3 x + 11 - x = \frac{3}{2} (\frac{4}{3} x + 12) + 7

6 x = - 1

x, 10 x - 5 y = 5

- 7 - 9 x = 20

What is the answer to solvefor A,z= A/(y^{10)}+Be^y ?
The answer to solvefor A,z= A/(y^{10)}+Be^y is A=zy^{10}-Be^yy^{10};\quad y\ne 0