What is the answer to (x+1)^2=x^2+2x+1 ?

The answer to (x+1)^2=x^2+2x+1 is True for all x

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(x+1)^2=x^2+2x+1

(x + 1)^{2} = x^{2} + 2 x + 1

True for all x

Solution steps

(x + 1)^{2} = x^{2} + 2 x + 1

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

x^{2} + 2 x + 1 = x^{2} + 2 x + 1

Move

1

to the right side

x^{2} + 2 x = x^{2} + 2 x

Subtract

x^{2} + 2 x

from both sides

x^{2} + 2 x - (x^{2} + 2 x) = x^{2} + 2 x - (x^{2} + 2 x)

Simplify

0 = 0

Both sides are equal

True for all x

4 (3 x + 1) - 4 = 3 (x + 3)

y, 4 x - 5 y = - 45

9^{2} + 4 0^{2} = 4 1^{2}

x, 2 x + 5 y - z = 8

25 = 20

What is the answer to (x+1)^2=x^2+2x+1 ?
The answer to (x+1)^2=x^2+2x+1 is True for all x
Solve for x: (x+1)^2=x^2+2x+1
The solution is True for all x