What are the solutions to the equation (-26-x)(-44-x)-40*40=0 ?

The solutions to the equation (-26-x)(-44-x)-40*40=0 are x=6,x=-76

Find the zeros of (-26-x)(-44-x)-40*40=0

The zeros of (-26-x)(-44-x)-40*40=0 are x=6,x=-76

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(- 26 - x) (- 44 - x) - 40 \cdot 40 = 0

x = 6, x = - 76

Solution steps

(- 26 - x) (- 44 - x) - 40 \cdot 40 = 0

Expand

(- 26 - x) (- 44 - x) - 40 \cdot 40 : x^{2} + 70 x - 456

x^{2} + 70 x - 456 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 \cdot 1 \cdot ( - 456 )}{2 \cdot 1}

7 0^{2} - 4 \cdot 1 \cdot (- 456) = 82

x_{1, 2} = \frac{- 70 \pm 82}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 70 + 82}{2 \cdot 1}, x_{2} = \frac{- 70 - 82}{2 \cdot 1}

x = \frac{- 70 + 82}{2 \cdot 1} : 6

x = \frac{- 70 - 82}{2 \cdot 1} : - 76

The solutions to the quadratic equation are:

x = 6, x = - 76

x^{5} - 6 x^{4} - 12 x^{3} + 82 x^{2} - 45 x + 300

\frac{∣ m ∣}{5} = 3

\frac{π \cdot 9 \cdot 1 0 ^{6}}{2} \cdot 0. 5^{4} \cdot \frac{3.0 1 ^{4}}{1 0 ^{12}}

\frac{3}{5} + 3

3 x^{2} - 7 x - 20

What are the solutions to the equation (-26-x)(-44-x)-40*40=0 ?
The solutions to the equation (-26-x)(-44-x)-40*40=0 are x=6,x=-76
Find the zeros of (-26-x)(-44-x)-40*40=0
The zeros of (-26-x)(-44-x)-40*40=0 are x=6,x=-76