What are the solutions to the equation p^2+22p-3=0 ?

The solutions to the equation p^2+22p-3=0 are p=-11+2sqrt(31),p=-11-2sqrt(31)

Find the zeros of p^2+22p-3=0

The zeros of p^2+22p-3=0 are p=-11+2sqrt(31),p=-11-2sqrt(31)

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p^{2} + 22 p - 3 = 0

p = - 11 + 231, p = - 11 - 231

Decimal Notation

p = 0.13552 \dots, p = - 22.13552 \dots

Solution steps

p^{2} + 22 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot (- 3) = 431

p_{1, 2} = \frac{- 22 \pm 4 31}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 22 + 4 31}{2 \cdot 1}, p_{2} = \frac{- 22 - 4 31}{2 \cdot 1}

p = \frac{- 22 + 4 31}{2 \cdot 1} : - 11 + 231

p = \frac{- 22 - 4 31}{2 \cdot 1} : - 11 - 231

The solutions to the quadratic equation are:

p = - 11 + 231, p = - 11 - 231

\frac{3 a}{10} + \frac{3}{5} = \frac{a}{25} + \frac{1}{2}

\frac{9}{4} z + \frac{1}{2} = 2

0. 1^{2}

3 (x - 4) = 4 - 2 x + 7

What are the solutions to the equation p^2+22p-3=0 ?
The solutions to the equation p^2+22p-3=0 are p=-11+2sqrt(31),p=-11-2sqrt(31)
Find the zeros of p^2+22p-3=0
The zeros of p^2+22p-3=0 are p=-11+2sqrt(31),p=-11-2sqrt(31)