What is the answer to x^4-2x^2=x^2(x^2-2) ?

The answer to x^4-2x^2=x^2(x^2-2) is True for all x

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x^4-2x^2=x^2(x^2-2)

x^{4} - 2 x^{2} = x^{2} (x^{2} - 2)

True for all x

Solution steps

x^{4} - 2 x^{2} = x^{2} (x^{2} - 2)

Expand

x^{2} (x^{2} - 2) : x^{4} - 2 x^{2}

x^{4} - 2 x^{2} = x^{4} - 2 x^{2}

Subtract

x^{4} - 2 x^{2}

from both sides

x^{4} - 2 x^{2} - (x^{4} - 2 x^{2}) = x^{4} - 2 x^{2} - (x^{4} - 2 x^{2})

Simplify

0 = 0

Both sides are equal

True for all x

4 c + 3 = 3 (c - 4)

y, p y + q y = - 4 y + 8

\frac{x}{a} - \frac{x}{a + b} = \frac{1}{a + b}

6 x - 2 (2 + 8 x) = 10 + 4 x

h, A = \frac{1}{2} h (b_{1} + b_{2})

What is the answer to x^4-2x^2=x^2(x^2-2) ?
The answer to x^4-2x^2=x^2(x^2-2) is True for all x
Solve for x: x^4-2x^2=x^2(x^2-2)
The solution is True for all x