What is factor x^2+2xy+y^2-4 ?

The solution to factor x^2+2xy+y^2-4 is (x+y+2)(x+y-2)

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factor x^2+2xy+y^2-4

factor

x^{2} + 2 x y + y^{2} - 4

(x + y + 2) (x + y - 2)

Solution steps

x^{2} + 2 x y + y^{2} - 4

Factor

x^{2} + 2 x y + y^{2} : (x + y)^{2}

= (x + y)^{2} - 4

Factor the number:

4 = 2^{2}

= (x + y)^{2} - 2^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x + y)^{2} - 2^{2} = ((x + y) + 2) ((x + y) - 2)

= ((x + y) + 2) ((x + y) - 2)

Remove parentheses:

(a) = a

= (x + y + 2) (x + y - 2)

\frac{1}{3} (x + 2) = \frac{2}{3} x + 4

\frac{5 - 7 i}{7 + 5 i}

∣ x - 4 ∣ \geq 8

∣ 2 x + 9 ∣ - 9 = x

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What is factor x^2+2xy+y^2-4 ?
The solution to factor x^2+2xy+y^2-4 is (x+y+2)(x+y-2)