What is the answer to (3(x+3))/2-2(2-3x)=8x-1-2(x+3) ?

The answer to (3(x+3))/2-2(2-3x)=8x-1-2(x+3) is x=-5

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(3(x+3))/2-2(2-3x)=8x-1-2(x+3)

\frac{3 ( x + 3 )}{2} - 2 (2 - 3 x) = 8 x - 1 - 2 (x + 3)

x = - 5

Solution steps

\frac{3 ( x + 3 )}{2} - 2 (2 - 3 x) = 8 x - 1 - 2 (x + 3)

Multiply both sides by

2

3 (x + 3) - 4 (2 - 3 x) = 16 x - 2 - 4 (x + 3)

Expand

3 (x + 3) - 4 (2 - 3 x) : 15 x + 1

Expand

16 x - 2 - 4 (x + 3) : 12 x - 14

15 x + 1 = 12 x - 14

Move

1

to the right side

15 x = 12 x - 15

Move

12 x

to the left side

3 x = - 15

Divide both sides by

3

x = - 5

5 = 4

x, \frac{2}{3} (x - 18 y) = 6 y

x, - 3 x + 2 y = 0

\frac{1}{4} z - 17 = - 16

What is the answer to (3(x+3))/2-2(2-3x)=8x-1-2(x+3) ?
The answer to (3(x+3))/2-2(2-3x)=8x-1-2(x+3) is x=-5
Solve for x: (3(x+3))/2-2(2-3x)=8x-1-2(x+3)
The solution is x=-5