What is the answer to solvefor p,(p+q)^2=p^2+q^2 ?

The answer to solvefor p,(p+q)^2=p^2+q^2 is p=0

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solvefor p,(p+q)^2=p^2+q^2

solve for

p, (p + q)^{2} = p^{2} + q^{2}

p = 0

Solution steps

(p + q)^{2} = p^{2} + q^{2}

Expand

(p + q)^{2} : p^{2} + 2 pq + q^{2}

p^{2} + 2 pq + q^{2} = p^{2} + q^{2}

Move

q^{2}

to the right side

p^{2} + 2 pq = p^{2}

Move

p^{2}

to the left side

2 pq = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

p = 0

x = \frac{2}{3} lo g_{b} (27) + 2 lo g_{b} (2) - lo g_{b} (3)

x^{2} + 10 x + 25 = (x + 5)^{2}

3 x - 2 x + 4 = 2 + x + 2

\frac{1}{2} + 2 = x - 27

30 + 4 x + 2 = 8 + 6 x

What is the answer to solvefor p,(p+q)^2=p^2+q^2 ?
The answer to solvefor p,(p+q)^2=p^2+q^2 is p=0