What is the answer to solvefor m,E= 1/2 mv^2+mgh ?

The answer to solvefor m,E= 1/2 mv^2+mgh is m=(2E)/(v^2+2hg);\quad v^2+2hg\ne 0

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solvefor m,E= 1/2 mv^2+mgh

solve for

m, E = \frac{1}{2} m v^{2} + m g h

m = \frac{2 E}{v ^{2} + 2 h g}; v^{2} + 2 h g \neq = 0

Solution steps

E = \frac{1}{2} m v^{2} + m g h

Switch sides

\frac{1}{2} m v^{2} + m g h = E

Multiply both sides by

2

m v^{2} + 2 m g h = 2 E

Factor

m v^{2} + 2 m g h : m (v^{2} + 2 h g)

m (v^{2} + 2 h g) = 2 E

Divide both sides by

v^{2} + 2 h g; v^{2} + 2 h g \neq = 0

m = \frac{2 E}{v ^{2} + 2 h g}; v^{2} + 2 h g \neq = 0

2 (x - 1) = 1 - (4 - 5 x)

y = - 4 y

G (x) = \frac{x}{6}

y = 2 + 4

\frac{3 x - 1}{4} - \frac{2 x + 1}{5} = \frac{7 x - 13}{20}

What is the answer to solvefor m,E= 1/2 mv^2+mgh ?
The answer to solvefor m,E= 1/2 mv^2+mgh is m=(2E)/(v^2+2hg);\quad v^2+2hg\ne 0