What is the answer to solvefor x,mx+y=m^2+mn+m-n ?

The answer to solvefor x,mx+y=m^2+mn+m-n is x=(m^2+mn+m-n-y)/m ;\quad m\ne 0

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solvefor x,mx+y=m^2+mn+m-n

solve for

x, m x + y = m^{2} + mn + m - n

x = \frac{m ^{2} + mn + m - n - y}{m}; m \neq = 0

Solution steps

m x + y = m^{2} + mn + m - n

Move

y

to the right side

m x = m^{2} + mn + m - n - y

Divide both sides by

m; m \neq = 0

x = \frac{m ^{2} + mn + m - n - y}{m}; m \neq = 0

5 (x + 9) - 4 = 51

3.2 x + 2.6 = - 23

5 (x - 6) + 6 = 7 x - 4

- 6 x - 10 = 20

\frac{2 x - 4}{5} + \frac{x}{2} = 2

What is the answer to solvefor x,mx+y=m^2+mn+m-n ?
The answer to solvefor x,mx+y=m^2+mn+m-n is x=(m^2+mn+m-n-y)/m ;\quad m\ne 0