What are the solutions to the equation 6p^2-5p-11=5p^2 ?

The solutions to the equation 6p^2-5p-11=5p^2 are p=(5+sqrt(69))/2 ,p=(5-sqrt(69))/2

Find the zeros of 6p^2-5p-11=5p^2

The zeros of 6p^2-5p-11=5p^2 are p=(5+sqrt(69))/2 ,p=(5-sqrt(69))/2

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6 p^{2} - 5 p - 11 = 5 p^{2}

p = \frac{5 + 69}{2}, p = \frac{5 - 69}{2}

Decimal Notation

p = 6.65331 \dots, p = - 1.65331 \dots

Solution steps

6 p^{2} - 5 p - 11 = 5 p^{2}

Move

5 p^{2}

to the left side

p^{2} - 5 p - 11 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 11) = 69

p_{1, 2} = \frac{- ( - 5 ) \pm 69}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 69}{2 \cdot 1}, p_{2} = \frac{- ( - 5 ) - 69}{2 \cdot 1}

p = \frac{- ( - 5 ) + 69}{2 \cdot 1} : \frac{5 + 69}{2}

p = \frac{- ( - 5 ) - 69}{2 \cdot 1} : \frac{5 - 69}{2}

The solutions to the quadratic equation are:

p = \frac{5 + 69}{2}, p = \frac{5 - 69}{2}

x x^{\frac{1}{2}}

x < - 10 and x < 10

12 - (\frac{9}{3})^{2}

100 x^{2} - 1

\frac{5}{3} a + 6 = \frac{7}{9}

What are the solutions to the equation 6p^2-5p-11=5p^2 ?
The solutions to the equation 6p^2-5p-11=5p^2 are p=(5+sqrt(69))/2 ,p=(5-sqrt(69))/2
Find the zeros of 6p^2-5p-11=5p^2
The zeros of 6p^2-5p-11=5p^2 are p=(5+sqrt(69))/2 ,p=(5-sqrt(69))/2