What is the answer to (x-1)(x+2)+3(2x+1)-(x-2)(x+2)=0 ?

The answer to (x-1)(x+2)+3(2x+1)-(x-2)(x+2)=0 is x=-5/7

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(x-1)(x+2)+3(2x+1)-(x-2)(x+2)=0

(x - 1) (x + 2) + 3 (2 x + 1) - (x - 2) (x + 2) = 0

x = - \frac{5}{7}

Decimal Notation

x = - 0.71428 \dots

Solution steps

(x - 1) (x + 2) + 3 (2 x + 1) - (x - 2) (x + 2) = 0

Expand

(x - 1) (x + 2) + 3 (2 x + 1) - (x - 2) (x + 2) : 7 x + 5

7 x + 5 = 0

Move

5

to the right side

7 x = - 5

Divide both sides by

7

x = - \frac{5}{7}

10 - 10 (2 + x) = - 10 x + 9

4.25 c - 0.75 = 4.35

335.5 - 282 x = 0

x, - 2 x - 5 y = 20

12 (x + 20) = 372

What is the answer to (x-1)(x+2)+3(2x+1)-(x-2)(x+2)=0 ?
The answer to (x-1)(x+2)+3(2x+1)-(x-2)(x+2)=0 is x=-5/7
Solve for x: (x-1)(x+2)+3(2x+1)-(x-2)(x+2)=0
The solution is x=-5/7