What is the answer to solvefor y,ysqrt(x^2-4)=x ?

The answer to solvefor y,ysqrt(x^2-4)=x is y= x/(sqrt(x^2-4));\quad x\ne 2,x\ne-2

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solvefor y,ysqrt(x^2-4)=x

solve for

y, y x^{2} - 4 = x

y = \frac{x}{x ^{2} - 4}; x \neq = 2, x \neq = - 2

Solution steps

y x^{2} - 4 = x

Divide both sides by

x^{2} - 4; x \neq = 2, x \neq = - 2

y = \frac{x}{x ^{2} - 4}; x \neq = 2, x \neq = - 2

y, y - 2 x = 3

y, y - 2 x = 4

u, 3 x - 2 y - z - u = - 6

a, h = \frac{a}{3}

x, x + (y + 1500) = 12800

What is the answer to solvefor y,ysqrt(x^2-4)=x ?
The answer to solvefor y,ysqrt(x^2-4)=x is y= x/(sqrt(x^2-4));\quad x\ne 2,x\ne-2