What is the answer to t=2-2[2t-3(1-t)] ?

The answer to t=2-2[2t-3(1-t)] is t= 8/11

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t=2-2[2t-3(1-t)]

t = 2 - 2 [2 t - 3 (1 - t)]

t = \frac{8}{11}

Decimal Notation

t = 0.72727 \dots

Solution steps

t = 2 - 2 [2 t - 3 (1 - t)]

Expand

2 - 2 (2 t - 3 (1 - t)) : - 10 t + 8

t = - 10 t + 8

Move

10 t

to the left side

11 t = 8

Divide both sides by

11

t = \frac{8}{11}

\frac{3 x}{4} - 1 = 4

j - (- 17) = 36

2 (4 x - 2) = 3 (5 x - 5)

\frac{3 x}{4} - 2 = 7

4 - 4 x = 0

What is the answer to t=2-2[2t-3(1-t)] ?
The answer to t=2-2[2t-3(1-t)] is t= 8/11
Solve for t: t=2-2[2t-3(1-t)]
The solution is t= 8/11