What is ((x-3)(x+7))/(x-4)<= 0 ?

The solution to ((x-3)(x+7))/(x-4)<= 0 is x<=-7\lor 3<= x<4

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((x-3)(x+7))/(x-4)<= 0

\frac{( x - 3 ) ( x + 7 )}{x - 4} \leq 0

x \leq - 7 or 3 \leq x < 4

Interval Notation

(- \infty, - 7] \cup [3, 4)

Solution steps

\frac{( x - 3 ) ( x + 7 )}{x - 4} \leq 0

Identify the intervals

x \leq - 7 or 3 \leq x < 4

\frac{2 m ^{4}}{( 3 m + 8 ) ( 4 m - 7 )} + \frac{4 m}{( 4 m - 7 ) ( 4 m - 1 )}

30 = (x - 4)^{2} - 5

110 + 3 x + 11 = 16 x + 4

4 x + 3 = 7

What is ((x-3)(x+7))/(x-4)<= 0 ?
The solution to ((x-3)(x+7))/(x-4)<= 0 is x<=-7\lor 3<= x<4