What is the answer to solvefor x,xy+x-2y-1=0 ?

The answer to solvefor x,xy+x-2y-1=0 is x=(2y+1)/(y+1);\quad y\ne-1

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solvefor x,xy+x-2y-1=0

solve for

x, x y + x - 2 y - 1 = 0

x = \frac{2 y + 1}{y + 1}; y \neq = - 1

Solution steps

x y + x - 2 y - 1 = 0

Move

2 y

to the right side

x y + x - 1 = 2 y

Move

1

to the right side

x y + x = 2 y + 1

Factor

x y + x : x (y + 1)

x (y + 1) = 2 y + 1

Divide both sides by

y + 1; y \neq = - 1

x = \frac{2 y + 1}{y + 1}; y \neq = - 1

x, 4 x - 5 y = - 20

x, 4 y - 5 x = 3 (4 x - 2 y + 1)

- x - 1 = 6 (- 6 x - 3)

8 (\frac{3}{4} m + 2) - 3 (\frac{1}{6} m - 4) = \frac{3}{2} m

\frac{x}{25} - \frac{4}{5} = - \frac{4}{5}

What is the answer to solvefor x,xy+x-2y-1=0 ?
The answer to solvefor x,xy+x-2y-1=0 is x=(2y+1)/(y+1);\quad y\ne-1