What is the answer to m^2x+5n-6=4(x+m-1) ?

The answer to m^2x+5n-6=4(x+m-1) is x=(4m+2-5n)/(m^2-4);\quad m\ne 2,m\ne-2

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m^2x+5n-6=4(x+m-1)

m^{2} x + 5 n - 6 = 4 (x + m - 1)

x = \frac{4 m + 2 - 5 n}{m ^{2} - 4}; m \neq = 2, m \neq = - 2

Solution steps

m^{2} x + 5 n - 6 = 4 (x + m - 1)

Expand

4 (x + m - 1) : 4 x + 4 m - 4

m^{2} x + 5 n - 6 = 4 x + 4 m - 4

Move

5 n

to the right side

m^{2} x - 6 = 4 x + 4 m - 4 - 5 n

Move

6

to the right side

m^{2} x = 4 x + 4 m + 2 - 5 n

Move

4 x

to the left side

m^{2} x - 4 x = 4 m + 2 - 5 n

Factor

m^{2} x - 4 x : x (m^{2} - 4)

x (m^{2} - 4) = 4 m + 2 - 5 n

Divide both sides by

m^{2} - 4; m \neq = 2, m \neq = - 2

x = \frac{4 m + 2 - 5 n}{m ^{2} - 4}; m \neq = 2, m \neq = - 2

2 (x - 3) + 4 x = 18

2 [2 x - 2 (3 x - 2)] = 3 x - 3

x, 3 (y + 2 x - 1) = x + 5 y

a, (a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

49 s + 5 s - 46 s - 4 s + 3 = 19

What is the answer to m^2x+5n-6=4(x+m-1) ?
The answer to m^2x+5n-6=4(x+m-1) is x=(4m+2-5n)/(m^2-4);\quad m\ne 2,m\ne-2