What is the answer to 2x^2+10x+6=(x+3)(2x+1)+3(x+1) ?

The answer to 2x^2+10x+6=(x+3)(2x+1)+3(x+1) is True for all x

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2x^2+10x+6=(x+3)(2x+1)+3(x+1)

2 x^{2} + 10 x + 6 = (x + 3) (2 x + 1) + 3 (x + 1)

True for all x

Solution steps

2 x^{2} + 10 x + 6 = (x + 3) (2 x + 1) + 3 (x + 1)

Expand

(x + 3) (2 x + 1) + 3 (x + 1) : 2 x^{2} + 10 x + 6

2 x^{2} + 10 x + 6 = 2 x^{2} + 10 x + 6

Move

6

to the right side

2 x^{2} + 10 x = 2 x^{2} + 10 x

Subtract

2 x^{2} + 10 x

from both sides

2 x^{2} + 10 x - (2 x^{2} + 10 x) = 2 x^{2} + 10 x - (2 x^{2} + 10 x)

Simplify

0 = 0

Both sides are equal

True for all x

y = (\frac{1}{4})^{1}

u - (4 - 2 u) = 7 (u - 1)

x, y - 1 = - 1 (x - 1)

\frac{1 - x}{15} = \frac{5 ^{- 1}}{2 ^{- 1}}

- 4 (x + 5) = \frac{5}{3} (3 x - 12)

What is the answer to 2x^2+10x+6=(x+3)(2x+1)+3(x+1) ?
The answer to 2x^2+10x+6=(x+3)(2x+1)+3(x+1) is True for all x
Solve for x: 2x^2+10x+6=(x+3)(2x+1)+3(x+1)
The solution is True for all x