What are the solutions to the equation 4t^2-2t-3=-6t ?

The solutions to the equation 4t^2-2t-3=-6t are t= 1/2 ,t=-3/2

Find the zeros of 4t^2-2t-3=-6t

The zeros of 4t^2-2t-3=-6t are t= 1/2 ,t=-3/2

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4 t^{2} - 2 t - 3 = - 6 t

t = \frac{1}{2}, t = - \frac{3}{2}

Decimal Notation

t = 0.5, t = - 1.5

Solution steps

4 t^{2} - 2 t - 3 = - 6 t

Move

6 t

to the left side

4 t^{2} + 4 t - 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 3) = 8

t_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- 4 + 8}{2 \cdot 4}, t_{2} = \frac{- 4 - 8}{2 \cdot 4}

t = \frac{- 4 + 8}{2 \cdot 4} : \frac{1}{2}

t = \frac{- 4 - 8}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

t = \frac{1}{2}, t = - \frac{3}{2}

3 = x^{2}

\frac{x - 6}{x + 1} \geq 0

\frac{3 + 5 i}{1 - i}

- 3 x^{4} - 6 x^{3} + 6 x + 3

What are the solutions to the equation 4t^2-2t-3=-6t ?
The solutions to the equation 4t^2-2t-3=-6t are t= 1/2 ,t=-3/2
Find the zeros of 4t^2-2t-3=-6t
The zeros of 4t^2-2t-3=-6t are t= 1/2 ,t=-3/2