What is the answer to solvefor f,f=(f+g)(x) ?

The answer to solvefor f,f=(f+g)(x) is f=(xg)/(1-x);\quad x\ne 1

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solvefor f,f=(f+g)(x)

solve for

f, f = (f + g) (x)

f = \frac{xg}{1 - x}; x \neq = 1

Solution steps

f = (f + g) (x)

Expand

(f + g) (x) : x f + xg

f = x f + xg

Move

x f

to the left side

f - x f = xg

Factor

f - x f : f (1 - x)

f (1 - x) = xg

Divide both sides by

1 - x; x \neq = 1

f = \frac{xg}{1 - x}; x \neq = 1

a, 9 = a + f

3 (x + 4) = 2 x - 1

3 x - 18 = 2 x

\frac{m}{- 7} + 9 = 11

x, - 6 x + 3 y = - 12

What is the answer to solvefor f,f=(f+g)(x) ?
The answer to solvefor f,f=(f+g)(x) is f=(xg)/(1-x);\quad x\ne 1