What is the answer to 16x-[3x-(6-9x)]=-30x-[-(3x-2)-(x-3)] ?

The answer to 16x-[3x-(6-9x)]=-30x-[-(3x-2)-(x-3)] is x=-11/30

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16x-[3x-(6-9x)]=-30x-[-(3x-2)-(x-3)]

16 x - [3 x - (6 - 9 x)] = - 30 x - [- (3 x - 2) - (x - 3)]

x = - \frac{11}{30}

Decimal Notation

x = - 0.36666 \dots

Solution steps

16 x - [3 x - (6 - 9 x)] = - 30 x - [- (3 x - 2) - (x - 3)]

Expand

16 x - (3 x - (6 - 9 x)) : 4 x + 6

Expand

- 30 x - (- (3 x - 2) - (x - 3)) : - 26 x - 5

4 x + 6 = - 26 x - 5

Move

6

to the right side

4 x = - 26 x - 11

Move

26 x

to the left side

30 x = - 11

Divide both sides by

30

x = - \frac{11}{30}

3 (x + 1) - 2 (3 x - 1) = 5 (x - 2) + 7

y = - 2 (1)^{2}

7 = - 13 + x

y, - 2 x - y = - 3

3 (x - 4 (x - 2)) - 2 (x - 1 (2 (- x + 2)) - 3) = 3 (x - 5)

What is the answer to 16x-[3x-(6-9x)]=-30x-[-(3x-2)-(x-3)] ?
The answer to 16x-[3x-(6-9x)]=-30x-[-(3x-2)-(x-3)] is x=-11/30
Solve for x: 16x-[3x-(6-9x)]=-30x-[-(3x-2)-(x-3)]
The solution is x=-11/30