What is the answer to solvefor A,BA+8=3mA ?

The answer to solvefor A,BA+8=3mA is A=-8/(B-3m);\quad m\ne B/3

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solvefor A,BA+8=3mA

solve for

A, B A + 8 = 3 m A

A = - \frac{8}{B - 3 m}; m \neq = \frac{B}{3}

Solution steps

B A + 8 = 3 m A

Move

8

to the right side

B A = 3 m A - 8

Move

3 m A

to the left side

B A - 3 m A = - 8

Factor

B A - 3 m A : A (B - 3 m)

A (B - 3 m) = - 8

Divide both sides by

B - 3 m; m \neq = \frac{B}{3}

A = - \frac{8}{B - 3 m}; m \neq = \frac{B}{3}

y = 29

3 (2 x + 1) = 15

39 - 5 k = 1 - 8 (- 8 - k)

4 (x - 2) = 20

f, f = in (\frac{1 + x}{1 - x})

What is the answer to solvefor A,BA+8=3mA ?
The answer to solvefor A,BA+8=3mA is A=-8/(B-3m);\quad m\ne B/3