What is the answer to (2x+3)(x+1)=2(x+1)^2+(x+1) ?

The answer to (2x+3)(x+1)=2(x+1)^2+(x+1) is True for all x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2x+3)(x+1)=2(x+1)^2+(x+1)

(2 x + 3) (x + 1) = 2 (x + 1)^{2} + (x + 1)

True for all x

Solution steps

(2 x + 3) (x + 1) = 2 (x + 1)^{2} + (x + 1)

(2 x + 3) (x + 1) = 2 (x + 1)^{2} + x + 1

Expand

(2 x + 3) (x + 1) : 2 x^{2} + 5 x + 3

Expand

2 (x + 1)^{2} + x + 1 : 2 x^{2} + 5 x + 3

2 x^{2} + 5 x + 3 = 2 x^{2} + 5 x + 3

Move

3

to the right side

2 x^{2} + 5 x = 2 x^{2} + 5 x

Subtract

2 x^{2} + 5 x

from both sides

2 x^{2} + 5 x - (2 x^{2} + 5 x) = 2 x^{2} + 5 x - (2 x^{2} + 5 x)

Simplify

0 = 0

Both sides are equal

True for all x

16 x - 1 = 12 x + 3

200 - \frac{x}{15} = 0

x, a (5 - x) = b x - 8

12 = 1 - 2 x + 5

0.7 + 0.2 (10 x + 4) = 3 x + 3.5 + 4 x

What is the answer to (2x+3)(x+1)=2(x+1)^2+(x+1) ?
The answer to (2x+3)(x+1)=2(x+1)^2+(x+1) is True for all x
Solve for x: (2x+3)(x+1)=2(x+1)^2+(x+1)
The solution is True for all x