What is the answer to solvefor m,y=mx+b_{2} ?

The answer to solvefor m,y=mx+b_{2} is m=(y-b_{2})/x ;\quad x\ne 0

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solvefor m,y=mx+b_{2}

solve for

m, y = m x + b_{2}

m = \frac{y - b _{2}}{x}; x \neq = 0

Solution steps

y = m x + b_{2}

Switch sides

m x + b_{2} = y

Move

b_{2}

to the right side

m x = y - b_{2}

Divide both sides by

x; x \neq = 0

m = \frac{y - b _{2}}{x}; x \neq = 0

x, \frac{x}{- 3} + \frac{y}{2} = 1

5 x - 7 = 0

5 x - 4 = 1

6 - (3 + x) = 10

6 x + 8 = 10 + 20

What is the answer to solvefor m,y=mx+b_{2} ?
The answer to solvefor m,y=mx+b_{2} is m=(y-b_{2})/x ;\quad x\ne 0