What is the answer to solvefor b,a(3b-1)=2b+2 ?

The answer to solvefor b,a(3b-1)=2b+2 is b=(2+a)/(3a-2);\quad a\ne 2/3

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solvefor b,a(3b-1)=2b+2

solve for

b, a (3 b - 1) = 2 b + 2

b = \frac{2 + a}{3 a - 2}; a \neq = \frac{2}{3}

Solution steps

a (3 b - 1) = 2 b + 2

Expand

a (3 b - 1) : 3 ba - a

3 ba - a = 2 b + 2

Move

a

to the right side

3 ba = 2 b + 2 + a

Move

2 b

to the left side

3 ba - 2 b = 2 + a

Factor

3 ba - 2 b : b (3 a - 2)

b (3 a - 2) = 2 + a

Divide both sides by

3 a - 2; a \neq = \frac{2}{3}

b = \frac{2 + a}{3 a - 2}; a \neq = \frac{2}{3}

5 x = 8 x

5 x = 17

3 (2 x - 4) = 7 - (x + 5)

y = 3 (- 2)^{2}

2 (3 n - 1) = 28

What is the answer to solvefor b,a(3b-1)=2b+2 ?
The answer to solvefor b,a(3b-1)=2b+2 is b=(2+a)/(3a-2);\quad a\ne 2/3