What is the answer to log_{10}(6)(x)+log_{10}(6)(x-9)=2 ?

The answer to log_{10}(6)(x)+log_{10}(6)(x-9)=2 is x=(2+9log_{10}(6))/(2log_{10)(6)}

Solve for x: log_{10}(6)(x)+log_{10}(6)(x-9)=2

The solution is x=(2+9log_{10}(6))/(2log_{10)(6)}

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lo g_{10} (6) (x) + lo g_{10} (6) (x - 9) = 2

x = \frac{2 + 9 lo g _{10} ( 6 )}{2 lo g _{10} ( 6 )}

Decimal Notation

x = 5.78509 \dots

Solution steps

lo g_{10} (6) (x) + lo g_{10} (6) (x - 9) = 2

lo g_{10} (6) x + lo g_{10} (6) (x - 9) = 2

Expand

lo g_{10} (6) (x - 9) : lo g_{10} (6) x - 9 lo g_{10} (6)

lo g_{10} (6) x + lo g_{10} (6) x - 9 lo g_{10} (6) = 2

Add similar elements:

lo g_{10} (6) x + lo g_{10} (6) x = 2 lo g_{10} (6) x

2 lo g_{10} (6) x - 9 lo g_{10} (6) = 2

Move

9 lo g_{10} (6)

to the right side

2 lo g_{10} (6) x = 2 + 9 lo g_{10} (6)

Divide both sides by

2 lo g_{10} (6)

x = \frac{2 + 9 lo g _{10} ( 6 )}{2 lo g _{10} ( 6 )}

a, 2 a - b = 5

8 x - 37 = - 109

x, 4 y = 3 x

36 x - 27 = 16 x + 10 x + 23

- 4 + w = - 10

What is the answer to log_{10}(6)(x)+log_{10}(6)(x-9)=2 ?
The answer to log_{10}(6)(x)+log_{10}(6)(x-9)=2 is x=(2+9log_{10}(6))/(2log_{10)(6)}
Solve for x: log_{10}(6)(x)+log_{10}(6)(x-9)=2
The solution is x=(2+9log_{10}(6))/(2log_{10)(6)}