What are the solutions to the equation 4x^2+4x=-13 ?

The solutions to the equation 4x^2+4x=-13 are x=-1/2+sqrt(3)i,x=-1/2-sqrt(3)i

Find the zeros of 4x^2+4x=-13

The zeros of 4x^2+4x=-13 are x=-1/2+sqrt(3)i,x=-1/2-sqrt(3)i

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4 x^{2} + 4 x = - 13

x = - \frac{1}{2} + 3 i, x = - \frac{1}{2} - 3 i

Solution steps

4 x^{2} + 4 x = - 13

Move

13

to the left side

4 x^{2} + 4 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 13}{2 \cdot 4}

Simplify

4^{2} - 4 \cdot 4 \cdot 13 : 83 i

x_{1, 2} = \frac{- 4 \pm 8 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8 3 i}{2 \cdot 4}, x_{2} = \frac{- 4 - 8 3 i}{2 \cdot 4}

x = \frac{- 4 + 8 3 i}{2 \cdot 4} : - \frac{1}{2} + 3 i

x = \frac{- 4 - 8 3 i}{2 \cdot 4} : - \frac{1}{2} - 3 i

The solutions to the quadratic equation are:

x = - \frac{1}{2} + 3 i, x = - \frac{1}{2} - 3 i

10 + 2 p > 4

100 x^{3} y

3 x - 8 \geq 5 x + 7

18 + 1

6 (3 - x) < 2 x + 12

What are the solutions to the equation 4x^2+4x=-13 ?
The solutions to the equation 4x^2+4x=-13 are x=-1/2+sqrt(3)i,x=-1/2-sqrt(3)i
Find the zeros of 4x^2+4x=-13
The zeros of 4x^2+4x=-13 are x=-1/2+sqrt(3)i,x=-1/2-sqrt(3)i