What is the answer to solvefor a,x^3+y^3=3axy ?

The answer to solvefor a,x^3+y^3=3axy is a=(x^3+y^3)/(3xy);\quad 3xy\ne 0

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solvefor a,x^3+y^3=3axy

solve for

a, x^{3} + y^{3} = 3 a x y

a = \frac{x ^{3} + y ^{3}}{3 x y}; 3 x y \neq = 0

Solution steps

x^{3} + y^{3} = 3 a x y

Switch sides

3 a x y = x^{3} + y^{3}

Divide both sides by

3 x y; 3 x y \neq = 0

a = \frac{x ^{3} + y ^{3}}{3 x y}; 3 x y \neq = 0

y = - 1 - 4

y, x = y - z

y, x = y - 7

2 (x + 10) = 2 (3 x - 8)

\frac{x}{3} = \frac{2}{5} b - 1

What is the answer to solvefor a,x^3+y^3=3axy ?
The answer to solvefor a,x^3+y^3=3axy is a=(x^3+y^3)/(3xy);\quad 3xy\ne 0