What is (2x^3y)/(3z^4)*(6xz^5)/(10y^5) ?

The solution to (2x^3y)/(3z^4)*(6xz^5)/(10y^5) is (2x^4z)/(5y^4)

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simplify (2x^3y)/(3z^4)*(6xz^5)/(10y^5)

simplify

\frac{2 x ^{3} y}{3 z ^{4}} \cdot \frac{6 x z ^{5}}{10 y ^{5}}

\frac{2 x ^{4} z}{5 y ^{4}}

Solution steps

\frac{2 x ^{3} y}{3 z ^{4}} \cdot \frac{6 x z ^{5}}{10 y ^{5}}

Cancel

\frac{6 x z ^{5}}{10 y ^{5}} : \frac{3 x z ^{5}}{5 y ^{5}}

= \frac{2 x ^{3} y}{3 z ^{4}} \cdot \frac{3 x z ^{5}}{5 y ^{5}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 x ^{3} y \cdot 3 x z ^{5}}{3 z ^{4} \cdot 5 y ^{5}}

Cancel the common factor:

3

= \frac{2 x ^{3} y x z ^{5}}{z ^{4} \cdot 5 y ^{5}}

Simplify

\frac{z ^{5}}{z ^{4}} : z

= \frac{2 x ^{3} y x z}{5 y ^{5}}

Simplify

\frac{y}{y ^{5}} : \frac{1}{y ^{4}}

= \frac{2 x ^{3} x z}{5 y ^{4}}

Simplify

x^{3} x : x^{4}

= \frac{2 x ^{4} z}{5 y ^{4}}

- 109 > \frac{p}{- 10} - 97

∣ x - 1 ∣ + ∣ x + 1 ∣ < 1

∣ 7 y - 5 ∣ = ∣ 5 - 7 y ∣

∣ (3 - 4 x) - 7 ∣ < \frac{1}{4}

3 x + 2 (4 x + 2) \leq 2 (6 x + 1)

What is (2x^3y)/(3z^4)*(6xz^5)/(10y^5) ?
The solution to (2x^3y)/(3z^4)*(6xz^5)/(10y^5) is (2x^4z)/(5y^4)