What is the answer to solvefor k,log_{10}(S)=log_{10}(c)+klog_{10}(A) ?

The answer to solvefor k,log_{10}(S)=log_{10}(c)+klog_{10}(A) is k=log_{A}(S/c);\quad A\ne 1

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solvefor k,log_{10}(S)=log_{10}(c)+klog_{10}(A)

solve for

k, lo g_{10} (S) = lo g_{10} (c) + k lo g_{10} (A)

k = lo g_{A} (\frac{S}{c}); A \neq = 1

Solution steps

lo g_{10} (S) = lo g_{10} (c) + k lo g_{10} (A)

Switch sides

lo g_{10} (c) + k lo g_{10} (A) = lo g_{10} (S)

Move

lo g_{10} (c)

to the right side

k lo g_{10} (A) = lo g_{10} (S) - lo g_{10} (c)

Divide both sides by

lo g_{10} (A); A \neq = 1

k = lo g_{A} (\frac{S}{c}); A \neq = 1

x 3 = 20

c, c (x) = \frac{x ^{3}}{100} + 8 + 20

a, an = 1

- 3 x + 1 = 28

x - 3 = \frac{x - 6}{4}

What is the answer to solvefor k,log_{10}(S)=log_{10}(c)+klog_{10}(A) ?
The answer to solvefor k,log_{10}(S)=log_{10}(c)+klog_{10}(A) is k=log_{A}(S/c);\quad A\ne 1