What is the answer to (7-2x)/4 =(-x+3)/8 ?

The answer to (7-2x)/4 =(-x+3)/8 is x= 11/3

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(7-2x)/4 =(-x+3)/8

\frac{7 - 2 x}{4} = \frac{- x + 3}{8}

x = \frac{11}{3}

Decimal Notation

x = 3.66666 \dots

Solution steps

\frac{7 - 2 x}{4} = \frac{- x + 3}{8}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(7 - 2 x) \cdot 8 = 4 (- x + 3)

Expand

(7 - 2 x) \cdot 8 : 56 - 16 x

Expand

4 (- x + 3) : - 4 x + 12

56 - 16 x = - 4 x + 12

Move

56

to the right side

- 16 x = - 4 x - 44

Move

4 x

to the left side

- 12 x = - 44

Divide both sides by

- 12

x = \frac{11}{3}

x + 7 = 7

x + 8 = 7

2 x + 4 + 12 x + 8 = 180

p = 2 l + 2 w, w

7 x - 2 = - 2 x - 29

What is the answer to (7-2x)/4 =(-x+3)/8 ?
The answer to (7-2x)/4 =(-x+3)/8 is x= 11/3
Solve for x: (7-2x)/4 =(-x+3)/8
The solution is x= 11/3