What is 3y+7=5,x^7x-3y=1 ?

The solution to 3y+7=5,x^7x-3y=1 is

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3y+7=5,x^7x-3y=1

3 y + 7 = 5, x^{7} x - 3 y = 1

Solution steps

[3 y + 7 = 5 x^{7} x - 3 y = 1]

Solve

3 y + 7 = 5 : y = - \frac{2}{3}

Plug the solutions

y = - \frac{2}{3}

into

x^{7} x - 3 y = 1

For

x^{7} x - 3 y = 1

, subsitute

y

with

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

3 y + 7 = 5, x^{7} x - 3 y = 1

are

\frac{3 x}{4} = 15

24 + 4 n = - (n + 6)

h, a = 2 π r^{2} + 2 π r h

x (x - 4) - 2 = x^{2} - 4 (x + 3)

- \frac{1}{6} \cdot x - \frac{1}{2} + 21 \cdot (x + 2) = \frac{- 6 \cdot ( x - 3 )}{7}