What are the solutions to the equation 3x^2+12x+81=15 ?

The solutions to the equation 3x^2+12x+81=15 are x=-2+3sqrt(2)i,x=-2-3sqrt(2)i

Find the zeros of 3x^2+12x+81=15

The zeros of 3x^2+12x+81=15 are x=-2+3sqrt(2)i,x=-2-3sqrt(2)i

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3 x^{2} + 12 x + 81 = 15

x = - 2 + 32 i, x = - 2 - 32 i

Solution steps

3 x^{2} + 12 x + 81 = 15

Move

15

to the left side

3 x^{2} + 12 x + 66 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 66}{2 \cdot 3}

Simplify

1 2^{2} - 4 \cdot 3 \cdot 66 : 182 i

x_{1, 2} = \frac{- 12 \pm 18 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 18 2 i}{2 \cdot 3}, x_{2} = \frac{- 12 - 18 2 i}{2 \cdot 3}

x = \frac{- 12 + 18 2 i}{2 \cdot 3} : - 2 + 32 i

x = \frac{- 12 - 18 2 i}{2 \cdot 3} : - 2 - 32 i

The solutions to the quadratic equation are:

x = - 2 + 32 i, x = - 2 - 32 i

2 x = x + 1

- \frac{( 2 ) ^{5}}{5} + \frac{13 ( 2 ) ^{3}}{3} - 36 (2)

3 lo g_{3} (2) - lo g_{3} (72)

\frac{1}{5} - \frac{2}{3} + 1

2 x < 0

What are the solutions to the equation 3x^2+12x+81=15 ?
The solutions to the equation 3x^2+12x+81=15 are x=-2+3sqrt(2)i,x=-2-3sqrt(2)i
Find the zeros of 3x^2+12x+81=15
The zeros of 3x^2+12x+81=15 are x=-2+3sqrt(2)i,x=-2-3sqrt(2)i