What is the answer to solvefor f,y=f(x+3)-2 ?

The answer to solvefor f,y=f(x+3)-2 is f=(y+2)/(x+3);\quad x\ne-3

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solvefor f,y=f(x+3)-2

solve for

f, y = f (x + 3) - 2

f = \frac{y + 2}{x + 3}; x \neq = - 3

Solution steps

y = f (x + 3) - 2

Switch sides

f (x + 3) - 2 = y

Move

2

to the right side

f (x + 3) = y + 2

Divide both sides by

x + 3; x \neq = - 3

f = \frac{y + 2}{x + 3}; x \neq = - 3

f, y = f (x + 3) + 2

- x + 11 = - 2 x + 6

- 3 (2 + m) - 7 + 3 m = - 5 + 2 (3 m - 1)

\frac{5 x}{12} - \frac{1}{4} = \frac{1}{6}

2 (0) - y = 4

What is the answer to solvefor f,y=f(x+3)-2 ?
The answer to solvefor f,y=f(x+3)-2 is f=(y+2)/(x+3);\quad x\ne-3