What is factor (6m^4n^7)/(12m^5n^{-8)} ?

The solution to factor (6m^4n^7)/(12m^5n^{-8)} is (n^{15})/(2m)

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factor (6m^4n^7)/(12m^5n^{-8)}

factor

\frac{6 m ^{4} n ^{7}}{12 m ^{5} n ^{- 8}}

\frac{n ^{15}}{2 m}

Solution steps

\frac{6 m ^{4} n ^{7}}{12 m ^{5} n ^{- 8}}

Cancel the common factor:

6

= \frac{m ^{4} n ^{7}}{2 m ^{5} n ^{- 8}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{m ^{4}}{m ^{5}} = \frac{1}{m ^{5 - 4}}

= \frac{n ^{7}}{2 n ^{- 8} m ^{5 - 4}}

Subtract the numbers:

5 - 4 = 1

= \frac{n ^{7}}{2 m n ^{- 8}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{n ^{7}}{n ^{- 8}} = n^{7 - (- 8)}

= \frac{n ^{7 - (- 8)}}{2 m}

Subtract the numbers:

7 - (- 8) = 15

= \frac{n ^{15}}{2 m}

3 + (- 4)

8^{- \frac{1}{2}} \cdot 8^{\frac{7}{6}}

2 x^{2} - 6 x + 2

6 p^{2} - 8 p = - 3

\frac{10 !}{6 !}

What is factor (6m^4n^7)/(12m^5n^{-8)} ?
The solution to factor (6m^4n^7)/(12m^5n^{-8)} is (n^{15})/(2m)