What is the answer to solvefor A,y=Ae^{-2x}+Be^{3x} ?

The answer to solvefor A,y=Ae^{-2x}+Be^{3x} is A=e^{2x}(y-e^{3x}B)

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solvefor A,y=Ae^{-2x}+Be^{3x}

solve for

A, y = A e^{- 2 x} + B e^{3 x}

A = e^{2 x} (y - e^{3 x} B)

Solution steps

y = A e^{- 2 x} + B e^{3 x}

Switch sides

A e^{- 2 x} + B e^{3 x} = y

Move

B e^{3 x}

to the right side

A e^{- 2 x} = y - B e^{3 x}

Divide both sides by

e^{- 2 x}

A = e^{2 x} (y - e^{3 x} B)

\frac{5}{7} x - \frac{5}{21} x = 3 x

3 x + 4 x + 5 x = 180

x, - 6 x + 6 y = 6

x, - 2 x + 2 y = 20

4 (x - 3) + 40 = 64 - 3 (x - 2)

What is the answer to solvefor A,y=Ae^{-2x}+Be^{3x} ?
The answer to solvefor A,y=Ae^{-2x}+Be^{3x} is A=e^{2x}(y-e^{3x}B)