What are the solutions to the equation 5x^2-x+8=0 ?

The solutions to the equation 5x^2-x+8=0 are x= 1/10+i(sqrt(159))/(10),x= 1/10-i(sqrt(159))/(10)

Find the zeros of 5x^2-x+8=0

The zeros of 5x^2-x+8=0 are x= 1/10+i(sqrt(159))/(10),x= 1/10-i(sqrt(159))/(10)

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5 x^{2} - x + 8 = 0

x = \frac{1}{10} + i \frac{159}{10}, x = \frac{1}{10} - i \frac{159}{10}

Solution steps

5 x^{2} - x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

(- 1)^{2} - 4 \cdot 5 \cdot 8 : 159 i

x_{1, 2} = \frac{- ( - 1 ) \pm 159 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 159 i}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 159 i}{2 \cdot 5}

x = \frac{- ( - 1 ) + 159 i}{2 \cdot 5} : \frac{1}{10} + i \frac{159}{10}

x = \frac{- ( - 1 ) - 159 i}{2 \cdot 5} : \frac{1}{10} - i \frac{159}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} + i \frac{159}{10}, x = \frac{1}{10} - i \frac{159}{10}

0.0 5^{2}

\frac{3}{4} + \frac{9}{8}

\frac{- x + 5}{x - 9} \geq 0

(\frac{8}{9})^{2}

x + 3 lo g_{\frac{1}{3}} (lo g_{3} (∣ 1 + x ∣)) \leq 0

What are the solutions to the equation 5x^2-x+8=0 ?
The solutions to the equation 5x^2-x+8=0 are x= 1/10+i(sqrt(159))/(10),x= 1/10-i(sqrt(159))/(10)
Find the zeros of 5x^2-x+8=0
The zeros of 5x^2-x+8=0 are x= 1/10+i(sqrt(159))/(10),x= 1/10-i(sqrt(159))/(10)