What is the answer to 7/3-1/6 j= 1/6 (2j-7) ?

The answer to 7/3-1/6 j= 1/6 (2j-7) is j=7

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7/3-1/6 j= 1/6 (2j-7)

\frac{7}{3} - \frac{1}{6} j = \frac{1}{6} (2 j - 7)

j = 7

Solution steps

\frac{7}{3} - \frac{1}{6} j = \frac{1}{6} (2 j - 7)

Expand

\frac{1}{6} (2 j - 7) : \frac{1}{3} j - \frac{7}{6}

\frac{7}{3} - \frac{1}{6} j = \frac{1}{3} j - \frac{7}{6}

Move

\frac{7}{3}

to the right side

- \frac{1}{6} j = - \frac{7}{2} + \frac{1}{3} j

Move

\frac{1}{3} j

to the left side

- \frac{1}{2} j = - \frac{7}{2}

Multiply both sides by

- 2

j = 7

m + 8 = 22

\frac{x - 2}{3} = 2 x + 1

\frac{5}{4} (20 x + 12) = - 35

lo g_{2} (16 - 31) = 5 - lo g_{2} (16)

0.7 x - 6 = 0.2 x + 8

What is the answer to 7/3-1/6 j= 1/6 (2j-7) ?
The answer to 7/3-1/6 j= 1/6 (2j-7) is j=7
Solve for j: 7/3-1/6 j= 1/6 (2j-7)
The solution is j=7