What are the solutions to the equation -x^2-x+4=0 ?

The solutions to the equation -x^2-x+4=0 are x=-(1+sqrt(17))/2 ,x=(sqrt(17)-1)/2

Find the zeros of -x^2-x+4=0

The zeros of -x^2-x+4=0 are x=-(1+sqrt(17))/2 ,x=(sqrt(17)-1)/2

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- x^{2} - x + 4 = 0

x = - \frac{1 + 17}{2}, x = \frac{17 - 1}{2}

Decimal Notation

x = - 2.56155 \dots, x = 1.56155 \dots

Solution steps

- x^{2} - x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 4 = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 17}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 17}{2 ( - 1 )} : - \frac{1 + 17}{2}

x = \frac{- ( - 1 ) - 17}{2 ( - 1 )} : \frac{17 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 17}{2}, x = \frac{17 - 1}{2}

7 (t - 3) > 4 (t - 8)

v^{2} + 10 v + 25

0.554 \cdot \frac{145.8}{178.5}

∣ 5 x - 9 ∣ = ∣ 4 x + 8 ∣

What are the solutions to the equation -x^2-x+4=0 ?
The solutions to the equation -x^2-x+4=0 are x=-(1+sqrt(17))/2 ,x=(sqrt(17)-1)/2
Find the zeros of -x^2-x+4=0
The zeros of -x^2-x+4=0 are x=-(1+sqrt(17))/2 ,x=(sqrt(17)-1)/2