What is the answer to solvefor y,2x(4x^2-4x+1)=y+x(8x)+4(2x) ?

The answer to solvefor y,2x(4x^2-4x+1)=y+x(8x)+4(2x) is y=8x^3-16x^2-6x

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solvefor y,2x(4x^2-4x+1)=y+x(8x)+4(2x)

solve for

y, 2 x (4 x^{2} - 4 x + 1) = y + x (8 x) + 4 (2 x)

y = 8 x^{3} - 16 x^{2} - 6 x

Solution steps

2 x (4 x^{2} - 4 x + 1) = y + x (8 x) + 4 (2 x)

Switch sides

y + x 8 x + 4 \cdot 2 x = 2 x (4 x^{2} - 4 x + 1)

Simplify

y + x (8 x) + 4 (2 x) : y + 8 x^{2} + 8 x

y + 8 x^{2} + 8 x = 2 x (4 x^{2} - 4 x + 1)

Move

8 x^{2}

to the right side

y + 8 x = 8 x^{3} - 16 x^{2} + 2 x

Move

8 x

to the right side

y = 8 x^{3} - 16 x^{2} - 6 x

10 x + 45 x - 13 = 11 (5 x + 6)

y = - 3^{2} - 2

3 y = 7 + 5 (y - 3)

4 = \frac{2}{3} x

y, 2 x + y = - 4

What is the answer to solvefor y,2x(4x^2-4x+1)=y+x(8x)+4(2x) ?
The answer to solvefor y,2x(4x^2-4x+1)=y+x(8x)+4(2x) is y=8x^3-16x^2-6x