What are the solutions to the equation x^2-12x+36=90 ?

The solutions to the equation x^2-12x+36=90 are x=3(2+sqrt(10)),x=3(2-sqrt(10))

Find the zeros of x^2-12x+36=90

The zeros of x^2-12x+36=90 are x=3(2+sqrt(10)),x=3(2-sqrt(10))

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x^{2} - 12 x + 36 = 90

x = 3 (2 + 10), x = 3 (2 - 10)

Decimal Notation

x = 15.48683 \dots, x = - 3.48683 \dots

Solution steps

x^{2} - 12 x + 36 = 90

Move

90

to the left side

x^{2} - 12 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 54) = 610

x_{1, 2} = \frac{- ( - 12 ) \pm 6 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 10}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 6 10}{2 \cdot 1}

x = \frac{- ( - 12 ) + 6 10}{2 \cdot 1} : 3 (2 + 10)

x = \frac{- ( - 12 ) - 6 10}{2 \cdot 1} : 3 (2 - 10)

The solutions to the quadratic equation are:

x = 3 (2 + 10), x = 3 (2 - 10)

6 (3)^{2}

3 n^{2} - 143 n + 1210 = 0

\frac{1}{6} \cdot 2

10 x + 8 = - 6

- 4 < x \leq 3

What are the solutions to the equation x^2-12x+36=90 ?
The solutions to the equation x^2-12x+36=90 are x=3(2+sqrt(10)),x=3(2-sqrt(10))
Find the zeros of x^2-12x+36=90
The zeros of x^2-12x+36=90 are x=3(2+sqrt(10)),x=3(2-sqrt(10))