What are the solutions to the equation 3x^2-6x=21 ?

The solutions to the equation 3x^2-6x=21 are x=1+2sqrt(2),x=1-2sqrt(2)

Find the zeros of 3x^2-6x=21

The zeros of 3x^2-6x=21 are x=1+2sqrt(2),x=1-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 6 x = 21

x = 1 + 22, x = 1 - 22

Solution steps

3 x^{2} - 6 x = 21

Move

21

to the left side

3 x^{2} - 6 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 21 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 21) = 122

x_{1, 2} = \frac{- ( - 6 ) \pm 12 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 12 2}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 12 2}{2 \cdot 3}

x = \frac{- ( - 6 ) + 12 2}{2 \cdot 3} : 1 + 22

x = \frac{- ( - 6 ) - 12 2}{2 \cdot 3} : 1 - 22

The solutions to the quadratic equation are:

x = 1 + 22, x = 1 - 22

- \frac{7}{3} \geq \frac{4 - 4 x}{5}

\frac{x}{5} - 3 < 5

- x^{2} = 11

x^{3} + 5 x^{2} - 9 x - 45 > 0

- 5 = \frac{a}{18}

What are the solutions to the equation 3x^2-6x=21 ?
The solutions to the equation 3x^2-6x=21 are x=1+2sqrt(2),x=1-2sqrt(2)
Find the zeros of 3x^2-6x=21
The zeros of 3x^2-6x=21 are x=1+2sqrt(2),x=1-2sqrt(2)